The Brooklyn Nets have signed rookie big man Jarrett Allen to a multiyear contract, the team announced Thursday.

The 6’11” Allen was selected by the Nets with the 22nd overall pick in last month’s NBA Draft.  He played just one season for the University of Texas, averaging 13.4 points, 8.4 rebounds and 1.5 blocks per game.

With the deal, Brooklyn now has Allen under team control for the next four years.  The 19-year-old will reportedly make $1,713,720 this season, which is currently the seventh highest salary on the team.  Per team policy, the Nets did not release the financial terms of the contract.

I said this back on the night of the Draft:  This is a high upside pick for Brooklyn.  The Nets think they’ve found their starting center of the future in Allen.  Right now he is extremely raw and could see some time in the G-League this season playing for the Long Island Nets. After trading Brook Lopez a few days prior to taking Allen, the team had a huge hole in the middle, so taking Allen was also a smart pick.  Timofey Mozgov, who came over in the Lopez trade along with D’Angelo Russell, will be the starting center for now.  However, Allen could see significant minutes right away playing behind Mozgov if he looks good in training camp and the preseason.  Justin Hamilton was the only other center on the roster, but he was traded away to the Toronto Raptors in the DeMarre Carroll deal.

There’s also the injury concern.  Allen was unable to play for Brooklyn’s Summer League team in Las Vegas due to a left hip flexor injury sustained in workouts leading up to the draft.  The Nets held him out of action as a precaution, but he could have used the reps.

Now that Allen has officially signed, Oklahoma City Thunder guard Terrance Ferguson is the only draftee who has yet to sign his rookie contract.